maximum_circular_subarray.cpp File Reference

C++ program for maximum contiguous circular sum problem using Kadane's Algorithm More...

#include <cassert>
#include <iostream>
#include <vector>

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Namespaces
namespace	dynamic_programming
	Dynamic Programming algorithms.

Functions
int	dynamic_programming::maxCircularSum (std::vector< int > &arr)
	returns the maximum contiguous circular sum of an array
static void	test ()
	Self-test implementation.
int	main (int argc, char *argv[])
	Main function.

Detailed Description

C++ program for maximum contiguous circular sum problem using Kadane's Algorithm

The idea is to modify Kadane’s algorithm to find a minimum contiguous subarray sum and the maximum contiguous subarray sum, then check for the maximum value between the max_value and the value left after subtracting min_value from the total sum. For more information, check Geeks For Geeks explanation page.

Definition in file maximum_circular_subarray.cpp.

Function Documentation

main()

int main	(	int	argc,
		char *	argv[] )

Main function.

Parameters

argc	commandline argument count (ignored)
argv	commandline array of arguments (ignored)

Returns

0 on exit

Definition at line 87 of file maximum_circular_subarray.cpp.

                                 {
     test();  // run self-test implementations
     return 0;
}

test()

static void test ( )

static

Self-test implementation.

Returns

void

Definition at line 64 of file maximum_circular_subarray.cpp.

                   {
    // Description of the test
    // Input: arr[] = {8, -8, 9, -9, 10, -11, 12}
    // Output: 22 
    // Explanation: Subarray 12, 8, -8, 9, -9, 10 gives the maximum sum, that is 22.
 
    int n = 7; // size of the array
    std::vector<int> arr = {8, -8, 9, -9, 10, -11, 12}; 
    assert(dynamic_programming::maxCircularSum(arr) == 22); // this ensures that the algorithm works as expected
 
    arr = {8, -8, 10, -9, 10, -11, 12};
    assert(dynamic_programming::maxCircularSum(arr) == 23);
 
    std::cout << "All tests have successfully passed!\n";
}