0_1_knapsack.cpp File Reference

Implementation of [0-1 Knapsack Problem] (https://en.wikipedia.org/wiki/Knapsack_problem) More...

#include <array>
#include <cassert>
#include <iostream>
#include <vector>

Include dependency graph for 0_1_knapsack.cpp:

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Namespaces
namespace	dynamic_programming
	Dynamic Programming algorithms.
namespace	Knapsack
	Implementation of 0-1 Knapsack problem.

Functions
template<size_t n>
int	dynamic_programming::knapsack::maxKnapsackValue (const int capacity, const std::array< int, n > &weight, const std::array< int, n > &value)
	Picking up all those items whose combined weight is below the given capacity and calculating the value of those picked items. Trying all possible combinations will yield the maximum knapsack value.
static void	test ()
	Function to test the above algorithm.
int	main ()
	Main function.

Detailed Description

Implementation of [0-1 Knapsack Problem] (https://en.wikipedia.org/wiki/Knapsack_problem)

Given weights and values of n items, put these items in a knapsack of capacity W to get the maximum total value in the knapsack. In other words, given two integer arrays val[0..n-1] and wt[0..n-1] which represent values and weights associated with n items respectively. Also given an integer W which represents knapsack capacity, find out the maximum value subset of val[] such that sum of the weights of this subset is smaller than or equal to W. You cannot break an item, either pick the complete item or don’t pick it (0-1 property)

Algorithm

The idea is to consider all subsets of items and calculate the total weight and value of all subsets. Consider the only subsets whose total weight is smaller than W. From all such subsets, pick the maximum value subset.

Author

Anmol

Pardeep

Definition in file 0_1_knapsack.cpp.

Function Documentation

main()

int main

(

void

)

Main function.

Returns

0 on exit

Definition at line 126 of file 0_1_knapsack.cpp.

           {
    // Testing
    test();
    return 0;
}

maxKnapsackValue()

template<size_t n>

int dynamic_programming::knapsack::maxKnapsackValue	(	const int	capacity,
		const std::array< int, n > &	weight,
		const std::array< int, n > &	value )

Picking up all those items whose combined weight is below the given capacity and calculating the value of those picked items. Trying all possible combinations will yield the maximum knapsack value.

Template Parameters

n	size of the weight and value array

Parameters

capacity	capacity of the carrying bag
weight	array representing the weight of items
value	array representing the value of items

Returns

maximum value obtainable with a given capacity.

Definition at line 51 of file 0_1_knapsack.cpp.

                                                    {
    std::vector<std::vector<int> > maxValue(n + 1,
                                            std::vector<int>(capacity + 1, 0));
    // outer loop will select no of items allowed
    // inner loop will select the capacity of the knapsack bag
    int items = sizeof(weight) / sizeof(weight[0]);
    for (size_t i = 0; i < items + 1; ++i) {
        for (size_t j = 0; j < capacity + 1; ++j) {
            if (i == 0 || j == 0) {
                // if no of items is zero or capacity is zero, then maxValue
                // will be zero
                maxValue[i][j] = 0;
            } else if (weight[i - 1] <= j) {
                // if the ith item's weight(in the actual array it will be at i-1)
                // is less than or equal to the allowed weight i.e. j then we
                // can pick that item for our knapsack. maxValue will be the
                // obtained either by picking the current item or by not picking
                // current item
 
                // picking the current item
                int profit1 = value[i - 1] + maxValue[i - 1][j - weight[i - 1]];
 
                // not picking the current item
                int profit2 = maxValue[i - 1][j];
 
                maxValue[i][j] = std::max(profit1, profit2);
            } else {
                // as the weight of the current item is greater than the allowed weight, so
                // maxProfit will be profit obtained by excluding the current item.
                maxValue[i][j] = maxValue[i - 1][j];
            }
        }
    }
 
    // returning maximum value
    return maxValue[items][capacity];
}

test()

static void test ( )

static

Function to test the above algorithm.

Returns

void

Definition at line 96 of file 0_1_knapsack.cpp.

                   {
    // Test 1
    const int n1 = 3;                             // number of items
    std::array<int, n1> weight1 = {10, 20, 30};   // weight of each item
    std::array<int, n1> value1 = {60, 100, 120};  // value of each item
    const int capacity1 = 50;                     // capacity of carrying bag
    const int max_value1 = dynamic_programming::knapsack::maxKnapsackValue(
        capacity1, weight1, value1);
    const int expected_max_value1 = 220;
    assert(max_value1 == expected_max_value1);
    std::cout << "Maximum Knapsack value with " << n1 << " items is "
              << max_value1 << std::endl;
 
    // Test 2
    const int n2 = 4;                               // number of items
    std::array<int, n2> weight2 = {24, 10, 10, 7};  // weight of each item
    std::array<int, n2> value2 = {24, 18, 18, 10};  // value of each item
    const int capacity2 = 25;                       // capacity of carrying bag
    const int max_value2 = dynamic_programming::knapsack::maxKnapsackValue(
        capacity2, weight2, value2);
    const int expected_max_value2 = 36;
    assert(max_value2 == expected_max_value2);
    std::cout << "Maximum Knapsack value with " << n2 << " items is "
              << max_value2 << std::endl;
}