midpoint_integral_method.cpp File Reference

A numerical method for easy approximation of integrals More...

#include <cassert>
#include <cmath>
#include <cstdint>
#include <cstdlib>
#include <functional>
#include <iostream>
#include <map>

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Namespaces
namespace	numerical_methods
	for assert
namespace	midpoint_rule
	Functions for the Midpoint Integral method implementation.

Functions
double	numerical_methods::midpoint_rule::midpoint (const std::int32_t N, const double h, const double a, const std::function< double(double)> &func)
	Main function for implementing the Midpoint Integral Method implementation.
double	numerical_methods::midpoint_rule::f (double x)
	A function f(x) that will be used to test the method.
double	numerical_methods::midpoint_rule::g (double x)
	A function g(x) that will be used to test the method.
double	numerical_methods::midpoint_rule::k (double x)
	A function k(x) that will be used to test the method.
double	numerical_methods::midpoint_rule::l (double x)
	A function l(x) that will be used to test the method.
static void	test (std::int32_t N, double h, double a, double b, bool used_argv_parameters)
	Self-test implementations.
int	main (int argc, char **argv)
	Main function.

Detailed Description

A numerical method for easy approximation of integrals

The idea is to split the interval into N of intervals and use as interpolation points the xi for which it applies that xi = x0 + i*h, where h is a step defined as h = (b-a)/N where a and b are the first and last points of the interval of the integration [a, b].

We create a table of the xi and their corresponding f(xi) values and we evaluate the integral by the formula: I = h * {f(x0+h/2) + f(x1+h/2) + ... + f(xN-1+h/2)}

Arguments can be passed as parameters from the command line argv[1] = N, argv[2] = a, argv[3] = b. In this case if the default values N=16, a=1, b=3 are changed then the tests/assert are disabled.

Author

ggkogkou

Definition in file midpoint_integral_method.cpp.

Function Documentation

f()

double numerical_methods::midpoint_rule::f

(

double

x

)

A function f(x) that will be used to test the method.

Parameters

x	The independent variable xi

Returns

the value of the dependent variable yi = f(xi) = sqrt(xi) + ln(xi)

Definition at line 90 of file midpoint_integral_method.cpp.

{ return std::sqrt(x) + std::log(x); }

g()

double numerical_methods::midpoint_rule::g

(

double

x

)

A function g(x) that will be used to test the method.

Parameters

x	The independent variable xi

Returns

the value of the dependent variable yi = g(xi) = e^(-xi) * (4 - xi^2)

Definition at line 97 of file midpoint_integral_method.cpp.

{ return std::exp(-x) * (4 - std::pow(x, 2)); }

k()

double numerical_methods::midpoint_rule::k

(

double

x

)

A function k(x) that will be used to test the method.

Parameters

x	The independent variable xi

Returns

the value of the dependent variable yi = k(xi) = sqrt(2*xi^3 + 3)

Definition at line 103 of file midpoint_integral_method.cpp.

{ return std::sqrt(2 * std::pow(x, 3) + 3); }

l()

double numerical_methods::midpoint_rule::l

(

double

x

)

A function l(x) that will be used to test the method.

Parameters

x	The independent variable xi

Returns

the value of the dependent variable yi = l(xi) = xi + ln(2*xi + 1)

Definition at line 109 of file midpoint_integral_method.cpp.

{ return x + std::log(2 * x + 1); }

main()

int main	(	int	argc,
		char **	argv )

Main function.

Parameters

argc	commandline argument count (ignored)
argv	commandline array of arguments (ignored)

Returns

0 on exit

Number of intervals to divide the integration interval.

MUST BE EVEN

Starting and ending point of the integration in

the real axis

Step, calculated by a, b and N

Definition at line 162 of file midpoint_integral_method.cpp.

                                {
    std::int32_t N =
        16;  
    double a = 1, b = 3;  
    double h = NAN;  
 
    bool used_argv_parameters =
        false;  // If argv parameters are used then the assert must be omitted
    // for the test cases
 
    // Get user input (by the command line parameters or the console after
    // displaying messages)
    if (argc == 4) {
        N = std::atoi(argv[1]);
        a = std::atof(argv[2]);
        b = std::atof(argv[3]);
        // Check if a<b else abort
        assert(a < b && "a has to be less than b");
        assert(N > 0 && "N has to be > 0");
        if (N < 4 || a != 1 || b != 3) {
            used_argv_parameters = true;
        }
        std::cout << "You selected N=" << N << ", a=" << a << ", b=" << b
                  << std::endl;
    } else {
        std::cout << "Default N=" << N << ", a=" << a << ", b=" << b
                  << std::endl;
    }
 
    // Find the step
    h = (b - a) / N;
 
    test(N, h, a, b, used_argv_parameters);  // run self-test implementations
 
    return 0;
}

midpoint()

double numerical_methods::midpoint_rule::midpoint	(	const std::int32_t	N,
		const double	h,
		const double	a,
		const std::function< double(double)> &	func )

Main function for implementing the Midpoint Integral Method implementation.

Parameters

N	is the number of intervals
h	is the step
a	is x0
func	is the function that will be integrated

Returns

the result of the integration

Definition at line 52 of file midpoint_integral_method.cpp.

                                                         {
    std::map<int, double>
        data_table;  // Contains the data points, key: i, value: f(xi)
    double xi = a;   // Initialize xi to the starting point x0 = a
 
    // Create the data table
    // Loop from x0 to xN-1
    double temp = NAN;
    for (std::int32_t i = 0; i < N; i++) {
        temp = func(xi + h / 2);  // find f(xi+h/2)
        data_table.insert(
            std::pair<std::int32_t, double>(i, temp));  // add i and f(xi)
        xi += h;  // Get the next point xi for the next iteration
    }
 
    // Evaluate the integral.
    // Remember: {f(x0+h/2) + f(x1+h/2) + ... + f(xN-1+h/2)}
    double evaluate_integral = 0;
    for (std::int32_t i = 0; i < N; i++) evaluate_integral += data_table.at(i);
 
    // Multiply by the coefficient h
    evaluate_integral *= h;
 
    // If the result calculated is nan, then the user has given wrong input
    // interval.
    assert(!std::isnan(evaluate_integral) &&
           "The definite integral can't be evaluated. Check the validity of "
           "your input.\n");
    // Else return
    return evaluate_integral;
}

test()

static void test ( std::int32_t N, double h, double a, double b, bool used_argv_parameters )

static

Self-test implementations.

Parameters

N	is the number of intervals
h	is the step
a	is x0
b	is the end of the interval
used_argv_parameters	is 'true' if argv parameters are given and 'false' if not

Definition at line 123 of file midpoint_integral_method.cpp.

                                            {
    // Call midpoint() for each of the test functions f, g, k, l
    // Assert with two decimal point precision
    double result_f = numerical_methods::midpoint_rule::midpoint(
        N, h, a, numerical_methods::midpoint_rule::f);
    assert((used_argv_parameters || (result_f >= 4.09 && result_f <= 4.10)) &&
           "The result of f(x) is wrong");
    std::cout << "The result of integral f(x) on interval [" << a << ", " << b
              << "] is equal to: " << result_f << std::endl;
 
    double result_g = numerical_methods::midpoint_rule::midpoint(
        N, h, a, numerical_methods::midpoint_rule::g);
    assert((used_argv_parameters || (result_g >= 0.27 && result_g <= 0.28)) &&
           "The result of g(x) is wrong");
    std::cout << "The result of integral g(x) on interval [" << a << ", " << b
              << "] is equal to: " << result_g << std::endl;
 
    double result_k = numerical_methods::midpoint_rule::midpoint(
        N, h, a, numerical_methods::midpoint_rule::k);
    assert((used_argv_parameters || (result_k >= 9.06 && result_k <= 9.07)) &&
           "The result of k(x) is wrong");
    std::cout << "The result of integral k(x) on interval [" << a << ", " << b
              << "] is equal to: " << result_k << std::endl;
 
    double result_l = numerical_methods::midpoint_rule::midpoint(
        N, h, a, numerical_methods::midpoint_rule::l);
    assert((used_argv_parameters || (result_l >= 7.16 && result_l <= 7.17)) &&
           "The result of l(x) is wrong");
    std::cout << "The result of integral l(x) on interval [" << a << ", " << b
              << "] is equal to: " << result_l << std::endl;
}