strings.min_cost_string_conversion¶
Algorithm for calculating the most cost-efficient sequence for converting one string into another. The only allowed operations are — Cost to copy a character is copy_cost — Cost to replace a character is replace_cost — Cost to delete a character is delete_cost — Cost to insert a character is insert_cost
Attributes¶
Functions¶
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Assembles the transformations based on the ops table. |
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Finds the most cost efficient sequence |
Module Contents¶
- strings.min_cost_string_conversion.assemble_transformation(ops: list[list[str]], i: int, j: int) list[str] ¶
Assembles the transformations based on the ops table.
>>> ops = [['0', 'Ic', 'Iu', 'It'], ... ['Dc', 'Cc', 'Iu', 'It'], ... ['Da', 'Da', 'Rau', 'Rat'], ... ['Dt', 'Dt', 'Rtu', 'Ct']] >>> x = len(ops) - 1 >>> y = len(ops[0]) - 1 >>> assemble_transformation(ops, x, y) ['Cc', 'Rau', 'Ct']
>>> ops1 = [['0']] >>> x1 = len(ops1) - 1 >>> y1 = len(ops1[0]) - 1 >>> assemble_transformation(ops1, x1, y1) []
- strings.min_cost_string_conversion.compute_transform_tables(source_string: str, destination_string: str, copy_cost: int, replace_cost: int, delete_cost: int, insert_cost: int) tuple[list[list[int]], list[list[str]]] ¶
Finds the most cost efficient sequence for converting one string into another.
>>> costs, operations = compute_transform_tables("cat", "cut", 1, 2, 3, 3) >>> costs[0][:4] [0, 3, 6, 9] >>> costs[2][:4] [6, 4, 3, 6] >>> operations[0][:4] ['0', 'Ic', 'Iu', 'It'] >>> operations[3][:4] ['Dt', 'Dt', 'Rtu', 'Ct']
>>> compute_transform_tables("", "", 1, 2, 3, 3) ([[0]], [['0']])
- strings.min_cost_string_conversion.m¶