project_euler.problem_085.sol1¶
Project Euler Problem 85: https://projecteuler.net/problem=85
By counting carefully it can be seen that a rectangular grid measuring 3 by 2 contains eighteen rectangles.  Although there exists no rectangular grid that contains exactly two million rectangles, find the area of the grid with the nearest solution.
Solution:
For a grid with side-lengths a and b, the number of rectangles contained in the grid is [a*(a+1)/2] * [b*(b+1)/2)], which happens to be the product of the a-th and b-th triangle numbers. So to find the solution grid (a,b), we need to find the two triangle numbers whose product is closest to two million.
Denote these two triangle numbers Ta and Tb. We want their product Ta*Tb to be as close as possible to 2m. Assuming that the best solution is fairly close to 2m, We can assume that both Ta and Tb are roughly bounded by 2m. Since Ta = a(a+1)/2, we can assume that a (and similarly b) are roughly bounded by sqrt(2 * 2m) = 2000. Since this is a rough bound, to be on the safe side we add 10%. Therefore we start by generating all the triangle numbers Ta for 1 <= a <= 2200. This can be done iteratively since the ith triangle number is the sum of 1,2, … ,i, and so T(i) = T(i-1) + i.
We then search this list of triangle numbers for the two that give a product closest to our target of two million. Rather than testing every combination of 2 elements of the list, which would find the result in quadratic time, we can find the best pair in linear time.
We iterate through the list of triangle numbers using enumerate() so we have a and Ta. Since we want Ta * Tb to be as close as possible to 2m, we know that Tb needs to be roughly 2m / Ta. Using the formula Tb = b*(b+1)/2 as well as the quadratic formula, we can solve for b: b is roughly (-1 + sqrt(1 + 8 * 2m / Ta)) / 2.
Since the closest integers to this estimate will give product closest to 2m, we only need to consider the integers above and below. It’s then a simple matter to get the triangle numbers corresponding to those integers, calculate the product Ta * Tb, compare that product to our target 2m, and keep track of the (a,b) pair that comes the closest.
Functions¶
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Find the area of the grid which contains as close to two million rectangles |
Module Contents¶
- project_euler.problem_085.sol1.solution(target: int = 2000000) int ¶
Find the area of the grid which contains as close to two million rectangles as possible. >>> solution(20) 6 >>> solution(2000) 72 >>> solution(2000000000) 86595