greedy_methods.gas_station¶
Task: There are n gas stations along a circular route, where the amount of gas at the ith station is gas_quantities[i].
You have a car with an unlimited gas tank and it costs costs[i] of gas to travel from the ith station to its next (i + 1)th station. You begin the journey with an empty tank at one of the gas stations.
Given two integer arrays gas_quantities and costs, return the starting gas station’s index if you can travel around the circuit once in the clockwise direction otherwise, return -1. If there exists a solution, it is guaranteed to be unique
Reference: https://leetcode.com/problems/gas-station/description
Implementation notes: First, check whether the total gas is enough to complete the journey. If not, return -1. However, if there is enough gas, it is guaranteed that there is a valid starting index to reach the end of the journey. Greedily calculate the net gain (gas_quantity - cost) at each station. If the net gain ever goes below 0 while iterating through the stations, start checking from the next station.
Classes¶
Functions¶
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This function returns the index from which to start the journey |
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This function returns a tuple of gas stations. |
Module Contents¶
- greedy_methods.gas_station.can_complete_journey(gas_stations: tuple[GasStation, Ellipsis]) int ¶
This function returns the index from which to start the journey in order to reach the end.
- Args:
gas_quantities [list]: Amount of gas available at each station cost [list]: The cost of gas required to move from one station to the next
- Returns:
start [int]: start index needed to complete the journey
Examples: >>> can_complete_journey(get_gas_stations([1, 2, 3, 4, 5], [3, 4, 5, 1, 2])) 3 >>> can_complete_journey(get_gas_stations([2, 3, 4], [3, 4, 3])) -1
- greedy_methods.gas_station.get_gas_stations(gas_quantities: list[int], costs: list[int]) tuple[GasStation, Ellipsis] ¶
This function returns a tuple of gas stations.
- Args:
gas_quantities: Amount of gas available at each station costs: The cost of gas required to move from one station to the next
- Returns:
A tuple of gas stations
>>> gas_stations = get_gas_stations([1, 2, 3, 4, 5], [3, 4, 5, 1, 2]) >>> len(gas_stations) 5 >>> gas_stations[0] GasStation(gas_quantity=1, cost=3) >>> gas_stations[-1] GasStation(gas_quantity=5, cost=2)