data_structures.binary_tree.merge_two_binary_trees

Problem Description: Given two binary tree, return the merged tree. The rule for merging is that if two nodes overlap, then put the value sum of both nodes to the new value of the merged node. Otherwise, the NOT null node will be used as the node of new tree.

Attributes

tree1

Classes

Node	A binary node has value variable and pointers to its left and right node.

Functions

merge_two_binary_trees(→ Node | None)	Returns root node of the merged tree.
print_preorder(→ None)	Print pre-order traversal of the tree.

Module Contents

class data_structures.binary_tree.merge_two_binary_trees.Node(value: int = 0)

A binary node has value variable and pointers to its left and right node.

left: Node | None = None

right: Node | None = None

value

data_structures.binary_tree.merge_two_binary_trees.merge_two_binary_trees(tree1: Node | None, tree2: Node | None) → Node | None

Returns root node of the merged tree.

>>> tree1 = Node(5)
>>> tree1.left = Node(6)
>>> tree1.right = Node(7)
>>> tree1.left.left = Node(2)
>>> tree2 = Node(4)
>>> tree2.left = Node(5)
>>> tree2.right = Node(8)
>>> tree2.left.right = Node(1)
>>> tree2.right.right = Node(4)
>>> merged_tree = merge_two_binary_trees(tree1, tree2)
>>> print_preorder(merged_tree)
9
11
2
1
15
4

data_structures.binary_tree.merge_two_binary_trees.print_preorder(root: Node | None) → None

Print pre-order traversal of the tree.

>>> root = Node(1)
>>> root.left = Node(2)
>>> root.right = Node(3)
>>> print_preorder(root)
1
2
3
>>> print_preorder(root.right)
3

data_structures.binary_tree.merge_two_binary_trees.tree1