project_euler.problem_207.sol1 ============================== .. py:module:: project_euler.problem_207.sol1 .. autoapi-nested-parse:: Project Euler Problem 207: https://projecteuler.net/problem=207 Problem Statement: For some positive integers k, there exists an integer partition of the form 4**t = 2**t + k, where 4**t, 2**t, and k are all positive integers and t is a real number. The first two such partitions are 4**1 = 2**1 + 2 and 4**1.5849625... = 2**1.5849625... + 6. Partitions where t is also an integer are called perfect. For any m ≥ 1 let P(m) be the proportion of such partitions that are perfect with k ≤ m. Thus P(6) = 1/2. In the following table are listed some values of P(m) P(5) = 1/1 P(10) = 1/2 P(15) = 2/3 P(20) = 1/2 P(25) = 1/2 P(30) = 2/5 ... P(180) = 1/4 P(185) = 3/13 Find the smallest m for which P(m) < 1/12345 Solution: Equation 4**t = 2**t + k solved for t gives: t = log2(sqrt(4*k+1)/2 + 1/2) For t to be real valued, sqrt(4*k+1) must be an integer which is implemented in function check_t_real(k). For a perfect partition t must be an integer. To speed up significantly the search for partitions, instead of incrementing k by one per iteration, the next valid k is found by k = (i**2 - 1) / 4 with an integer i and k has to be a positive integer. If this is the case a partition is found. The partition is perfect if t os an integer. The integer i is increased with increment 1 until the proportion perfect partitions / total partitions drops under the given value. Functions --------- .. autoapisummary:: project_euler.problem_207.sol1.check_partition_perfect project_euler.problem_207.sol1.solution Module Contents --------------- .. py:function:: check_partition_perfect(positive_integer: int) -> bool Check if t = f(positive_integer) = log2(sqrt(4*positive_integer+1)/2 + 1/2) is a real number. >>> check_partition_perfect(2) True >>> check_partition_perfect(6) False .. py:function:: solution(max_proportion: float = 1 / 12345) -> int Find m for which the proportion of perfect partitions to total partitions is lower than max_proportion >>> solution(1) > 5 True >>> solution(1/2) > 10 True >>> solution(3 / 13) > 185 True